WebSolution. Since tangents from an exterior point to a circle are equal in length. ∴ AD = AF [Tangents from A] BD = BE [Tangents from B] CE = CF [Tangents from C] Now, AB = AC. ⇒ AB – AD = AC – AD [Subtracting AD from both sides] ⇒ AB – AD = AC – AF [Using (i)] WebSep 29, 2024 · In figure, DE AB and BD BEF. D E A B and B D B E F. Prove that DC 2 = C F × AC D C 2 = C F × A C class-10 triangles Share It On 1 Answer 0 votes answered Sep 29, …
11 In fig. AB DE and BD EF. Prove that DC2 = CF * AC
WebMar 26, 2024 · In the given figure, DE AB and FE DB. Prove that DC2 = CF.AC 0 An important question from similarity chapter as it is already been asked in previous year … WebSolution The correct option is A CF ×AC Given : I n Δ ABC, AB DE and BD EF To prove : DC2 =CF ×AC Proof : I n Δ BCD, EF BD (Given) CF DC = CE CB....(1) (By corollary of BPT) I n … langhorst herne
Question 9In figure, AB DE , AB = DE , AC DF and AC = DF. Prove …
WebSummary: A parallelogram is a quadrilateral with two pairs of parallel sides. The opposite sides of a parallelogram are equal in length, and the opposite angles are equal in measure. In Fig. 8.11, AB DE, AB = DE, AC DF and AC = DF. It is proven that BC EF and BC = EF. WebProve that DC2 = CF × AC. from Mathematics Triangles Class 10 CBSE Triangles Advertisement Zigya App In the Fig, AB DE and BD EF. Prove that DC2 = CF × AC. 149 … WebJan 28, 2024 · Solution For 22. In fig. AB∥DE and BD∥EF. Prove that DC2=CF×AC 23. In the given figure, O is the centre of a circle. AB is a chord and th langille athletic centre hours